What are possible units for the reaction rate? A. L middot mol^-1 middot s^-1 B.

Question

What are possible units for the reaction rate? A. L middot mol^-1 middot s^-1 B. L^2 middot mol^-2 middot s^-1 C. s^-1 D. s^-2 E. mol middot L^-1 middot s^-1 2. Rate constant for a reaction is 4.65 L middot mol^-1 middot s^- 1. What is the overall order of the reaction? A. 0 B. 1 C. 2 D. 3 E. More information is needed to determine the overall order. 3. For the reaction A + 2B rightarrow C, which expression is correct? A. delta[C]/delta t = delta[A]/delta t B. delta[C]/delta t = 2 delta[B]/delta t C. delta[C]/delta t = -2 delta [B]/delta t D. delta [C]/delta t = - 1/2 delta [B]/delta t E. delta[C]/delta t = -1/2 delta [A]/delta t 4. For the overall chemical reaction shown here, which one of the following statements can be rightly assumed? 2H_2S(g) + O_2(g) rightarrow 2S(s) + 2H_2O(l) A. The reaction is third-order overall. B. The reaction is second-order overall. C. The rate law is: rate = k[H_2S]^2 [O_2]. D. The rate law is: rate = k[H_2S][O_2]. E. The rate law cannot be determined from the information given. The reaction A + 2B rightarrow products was found to have the rate law, rate = K[A][B]^2. While holding the concentration of A constant, the concentration of B is increased to three times its initial value. By what factor does the rate of reaction increase? A. 3 B. 6 C. 9 D. 27 E. 30

Explanation / Answer

Q1.

posible units of reaction rates are mainly:

Rate = k*[C]^n

Rate = M/s = mol / (L-s)

and [C] = M or mol /L

so

n changes, the time remains always the same, i.e on the BOTTOM

ignore D, since it is to the second power

zero order = mol/(L-s)

1st order = 1/(s)

2nd order = L/(mol -s)

3rd order = L^2 /(mol^2 -s)

therefore,

a)

this is true, for 2nd order

b)

this is true, for 3rd order

c)

this is true for 1s otrder

d)

this is false

e)

this is true, for zeroth order

Related Questions

Navigate

• Browse (All)
• Browse W
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.