Oxidation Number (or Oxidation State) rules: Elements have an oxidation number o
ID: 537270 • Letter: O
Question
Oxidation Number (or Oxidation State) rules: Elements have an oxidation number of 0 Group I and II - In addition to the elemental oxidation state of 0. Group I has an oxidation state of +1 and Group II has an oxidation state of +2. Hydrogen -usually +1, except when bonded to Group I or Group II, when it forms hydrides. -1. Oxygen - usually +2, except when it forms a O-O single bond, a peroxide, when it is -1. Fluorine is always -1 Other halogens are usually -1. except when bonded to O. 1. Determine the oxidation number of each atom in the following substancesExplanation / Answer
Q1.
a)
NF3 = N+3 and F= -1
b)
K2Cr2O7
since this is neutral
K2Cr2O7 = 0
2*K + 2*Cr + 7*O
O = -2 typpically, and K = +1 always so
2*1 + 2*Cr + 7*(-2) = 0
2Cr = 14 - 2
Cr = 12/2 = +6
c)
NO3-
O = -2 typically so
N + 3(-2) = -1
N = -1+6 = +5
d)
HClO4
O = -2 typically
H = +1 tpycally
so
Cl = ?
HClO4 = 0
+1 + Cl + 4*(-2) = 0
Cl = 8-1 = +7
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