This is all one question on my homework. The reaction above shows the reduction
ID: 537857 • Letter: T
Question
This is all one question on my homework.
The reaction above shows the reduction of an hematite ore (Fe2O3) to iron (Fe). What was the oxidation state of the elemental carbon atoms?
The reaction above shows the reduction of an hematite ore (Fe2O3) to iron (Fe). Is the oxidation state of the Fe3+ ions real or assigned?
The reaction above shows the reduction of an hematite ore (Fe2O3) to iron (Fe). What is the oxidation state of the C in CO2?
The reaction above shows the reduction of an hematite ore (Fe2O3) to iron (Fe).Is the oxidation state of the C in CO2 real or assigned?
The reaction above shows the reduction of an hematite ore (Fe2O3) to iron (Fe). What happened to the oxidation state of the carbon atoms during the reaction?
The reaction above shows the reduction of an hematite ore (Fe2O3) to iron (Fe). Which of the following explains the change in the oxidation state of C?
Each C4+ gained 4 electrons to become neutral. [+4 + (-4) = 0]
Each neutral C lost 4 electrons to become 4+. [0 - (-4) = +4]
Each neutral C gained 4 electrons to become 4+. [0 + (-4) = +4]
Each C4+ lost 4 electrons to become neutral. [+4 - (-4) = 0]
The reaction above shows the reduction of an hematite ore (Fe2O3) to iron (Fe). Reduction is the process of gaining electrons. Oxidation is the process of losing electrons. Did C undergo reduction or oxidation to become C4+ in CO2?
a.Each C4+ gained 4 electrons to become neutral. [+4 + (-4) = 0]
b.Each neutral C lost 4 electrons to become 4+. [0 - (-4) = +4]
c.Each neutral C gained 4 electrons to become 4+. [0 + (-4) = +4]
d.Each C4+ lost 4 electrons to become neutral. [+4 - (-4) = 0]
Explanation / Answer
Let me answer all of your questions one by one .
The balanced reaction is
2Fe2O3 + 3C = 4Fe + 3CO2
The oxidation of elemental carbon in reactants is 0.
The oxidation of iron in Fe3+ ions is +3 , and it is real , since the oxidation state of oxygen atoms is -2 , and for the whole compound it should be 0.
So if we assume Fe oxidation state to be x , then ,
2 x + (3 x -2) = 0
x = +3
The oxidation of C in CO2 is +4.
The oxidation state of carbon in in CO2 = +4 , is real , since the oxidation state of oxygen here is -2 , and total charge of the compound is 0.
The carbon had 0 oxidation state in reactants side which increased to +4 in products , hence the oxidation of carbon has took place .
Ans b) each neutral C lost 4 electrons to become 4+ [ 0 - (-4) = +4 ]
Since carbon has lost 4 electrons , and its oxidation state has become +4 in products side , it has undergone oxidation .
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