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plinglearning.com/ibiscms/mod/ibis/view.php?id-3594600 Virginia Northern Community College- CHEM 108-Summer17- BROWN 1 Activities and Due Dates I Final Exam 6/30/2017 11:55 PM e Gradebo Periodic Table stion 8 of 55 Sapling Learning Map d The temperature of an object increases by 42.4 when it absorbs 3833 J of heat. Calculate the heat y of the object. Number The mass of the object is 377 g Use this table of specific heats to identify the object Substance Specific heat Object Gold 0.129 0 240 0444 Aluminum 0.900 Sher O Iron O Aluminum Gold Iron Previous extSave And Exit g Inc. about us careers privacy

Explanation / Answer

Q = mc dT

c = Q/m dT = 3833 / 377 * 42.4 = 0.239 J/g 0C

hence the object is silver.

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