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Question

saplinglearning.com/ibiscms/mod/ibis/view.php?id-3594600 West Virginia Northern Community Virginia Northern Community College - CHEM 108-Summer17-BROWN | Activities and Due Dates | Final Exanm 6/30/2017 1155 PM 4 6/26/2017 05:44 PM Gradebook Perlodic Table Question 25 of 55 Sapling Learning Map In a constant-pressure calorimeter, 70.0 mL of 0.840 M HS04 was added to 70.0 mL of 0.460 M NaOH. The reaction caused the temperature of the solution to nse for 24.3 - to27 51 if the solution has the same density and specific heat as water (1.00 g/mL and 4.184 Jig K, respectively), what is for this reaction (per mole of H20 produced)? Assume that the total volume is the sum of the individual volumes Number kJ/mol H,O

Explanation / Answer

Calorimetry

H2SO4 + 2NaOH --> Na2SO4 + 2H2O

limiting reagent = H2SO4

moles of H2O formed = 0.840 M x 0.07 L = 0.0588 mol

Total mass of solution = 70 + 70 = 140 g

dT = 27.51 - 24.38 oC

So,

dH reaction = mCpdT/moles water

                   = 140 x 4.184 (27.51 - 24.38)/0.0588

                   = 31.181 kJ/mol

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