The titration of 70.00 mL of an unknown concentration of critic acid (H_3 C_6 H_

Question

The titration of 70.00 mL of an unknown concentration of critic acid (H_3 C_6 H_5 O_7) solution required 148.10 mL of 0.1986 M NaOH solution. Give the balanced reaction below, calculate the concentration (in M) of citric acid. H_3 C_6 H_5 O_7 (aq) + 3 NaOH (aq) rightarrow Na_3 C_6 H_5 O_7 (aq) + 3 H_2 O(1) A sample of gas has a mass of 0.5388 g, and 224 mL of gas were collected over water at a temperature of 55.0 degree C and at a barometric pressure of 999.6 torr. Given the vapor pressure of water at 55.0 degree C is 118.2 torr. calculate the molar mass of the gas (in g/mol).

Explanation / Answer

Ans 29.

The concentration of the acid can be calculated using the formula

M1 V1 / n1 = M2 V2/ n2

where M is the molarity , V is the volume and n is the number of moles .

putting all the values in the formula , we get ,

(M1 x 70.00) / 1 = ( 0.1986 x 148.10) / 3

M1 =0.1400 M

So the concentration of citric acid is 0.1400 M

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