Write the balanced chemical equation for the synthesis of strontium iodate monoh

Question

Write the balanced chemical equation for the synthesis of strontium iodate monohydrate from strontium nitrate, potassium iodate, and water. Be sure to include the water in the formula for strontium iodate monohydrate. Consult your textbook for instruction on writing hydrate formulas. Which compound will you be weighing at the end of this experiment? Calculate the molar masses for each reactant and product. For each trial, you are asked to determine the limiting reactant and the theoretical yield of strontium iodate monohydrate. Look in the experiment procedure for the mass of reactants assigned for each trial. Use these values to calculate the limiting reactant and the theoretical yield for each trial. (You will repeat these calculations during the experiment using measured masses.)

Explanation / Answer

Solution:

211.628 g of Sr(NO3)2 produces 455.438 g of product

213.9998 g of KIO3 produces 455.438 g of product

so the limiting reagent and theoretical yield are,

455.438 / 211.628 = 2.15 mol of Sr(NO3)2 required

455.438 / 213.9998 = 2.128 mol of KIO3 required

limiting reagent = KIO3

theoretical yield = (1/213.998)*(1/2)*(455.438/1) = 1.064 g of product

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