A 0.9% NaCl (saline) and 5% glucose solutions are considered isotonic to red blo
ID: 538985 • Letter: A
Question
A 0.9% NaCl (saline) and 5% glucose solutions are considered isotonic to red blood cells. If a cell is placed in a hypotonic solution hemolysis (bursting) takes place: if a cell is placed in a hypertonic solution crenation (shrinking) takes place. State whether each of the following solutions is hypotonic, hypertonic, or isotonic to red blood cells and whether crenation, hemolysis, or no change will take place. The degree of dissociation or ionization determines whether an electrolyte will be classified as strong or weak. In a solution of NaCl, 100% ionization takes place: this is represented by: NaCl(a) HOH rightarrow Na^+_(aq) + Cl^-_(aq) Give an example of another strong electrolyte and write its equation. The equation used to represent a weak electrolyte is similar to the one given above but it has a double arrow indicating that both ions and molecules are present: this is represented by: NH_4 OH_() HOH rightarrow NH_4^+_(aq) + OH^-_(aq) Give another example of a weak electrolyte and write its equation. A solution of a nonelectrolyte contains only molecules (not ions). Sucrose is a non-electrolyte: this process is represented by: C_12 H_22 O_11(s) HOH rightarrow C_12 F_22 O_11(aq) Give an example of another nonelcetrolyte and write its equation.Explanation / Answer
Ans 1.
a) 3% NaCl
Since 0.9% NaCl is isotonic to red blood cells , so 3% NaCl is hypertonic to red blood cells.
Crenation (Shrinkage) of red blood cells will occur.
b) 5% glucose
5% glucose is isotonic to red blood cells as mentioned in the question .
Since the solution is isotonic to the cells No change will be observed in them .
c) Pure H2O
Pure water does not have any amount dissolved solutes in it , so it is hypotonic to the Red blood cells .
The hemolysis of RBC will occur in pure water.
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