Using the following table: SHOW YOUR WORK! 16. Determine the reaction concentrat

Question

Using the following table:

SHOW YOUR WORK!

16. Determine the reaction concentrations of HCl and Na,S,O, using the following equations. For Example: Stock solution A] x drops of A (in well) total drops in well = final concentration [HCI] x drops of HCl total drops in wlf cocentration 0.5 M HCI x 12 drops of HCI 20 total drops = 0.3 M Note: Because you are reaching the same amount of moles of the product (the solid that blocks the view of the "X"), the same amount of moles of the reactants are being used for each trial (M). Therefore, this number should be the same for each trial. Since you are using a ratio to determine the exponents m and n, when you divide one rate by the other, that number of moles will cancel. This is why you only have the rate in sec instead of in the units of M sec

Explanation / Answer

Final concentration ={[stock solution A] X drops of A (in well)} / total drops in well

So, for well # C1,D1:

final reaction concentration of HCl = (1 X 12)/ (12 + 8) = 0.6 M,

and, final concentration of Na2S2O3 = (8X0.3)/(12 + 8) = 0.12 M

For well # C2,D2:

Final reaction concentration of HCl = (1 X 6)/(6 + 6 + 8) =0.3 M

Final reaction concentration of Na2S2O3 = (0.3 X 8)/ (6 +6 + 8) = 0.12 M

For well # C3,D3:

Final reaction concentration of HCl = (1 X 4)/(4 + 8 + 8) = 0.2 M

Final reaction concentration of Na2S2O3 = (0.3 X 8)/ (4 +8 + 8) =0.12 M

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