1.Toluene (C7H8 ) and nitric acid (HNO3 ) are used in the production of trinitro

Question

1.Toluene (C7H8 ) and nitric acid (HNO3 ) are used in the production of trinitrotoluene (TNT , C7H5N3O6 ), an explosive.
C7H8+HNO3C7H5N3O6+H2O (not balanced)

A) What mass in grams of nitric acid is required to react with 424 g C7H8 ?

B) What mass in grams of TNT can be made from 265 g C7H8 ?

2.A sugar crystal contains approximaely 1.9 x 1017 sucrose (C12 H22 O11 ) molecules. What is its mass in grams?

3.An experiment requires 0.045 ,ol of glucose, C6 H12 O6 What mass of glucose is this? Report answer in grams

Explanation / Answer

a)

mass of nitric acid reuqired

MW of toluene = 92.14 g/mol

mol of toluene = mass/MW = 424 /92.14 = 4.6017 mol of toluene

now;

C7H8+HNO3C7H5N3O6+H2O

balance

C7H8+3HNO3C7H5N3O6+ 3H2O

raito is 1 mol of toluene = 3 mol of nitric acid

4.6017 mol of toluene = 3*4.6017 = 13.8051 mol of nitric acid required

mass = mol*MW = 13.8051*63

mass of HNO3 = 869.7213g

b)

mass of TNT from

265 g of toluene

1 mol of toluene = 1 mol of TNT

mol of toluene = mass/MW = 265/92.14 = 2.8760 mol of toluene

mol of TNT = 2.8760

mass of TNT = mol*MW = 2.8760*227.13 = 653.2 g of TNT

Q2.

1 mol = 6.022*10^23 molecules

x mol = 1.9*10^17 molecules

x = (1.9*10^17) / (6.022*10^23) = 3.155*10^-7 mol

1 mol = 342.29 g

342.29 g = 3.155*10^-7 mol

mass = mol*MW =(342.29)(3.155*10^-7) = 0.0001079 g of sucrose

Q3.

1 mol of glucose= 180 g

0.045 mol of glucose = x

x = 0.045*180

x= 8.1 g of glucose

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