periment 9 eirrthanol and n-heptane, explain the difference in valuses of these

Question

periment 9 eirrthanol and n-heptane, explain the difference in valuses of these subhstances,based Using the liquids, 1-propanol and acetone, explain the difference in Ar values of these substances based on their intermolecular forces Using the liquids, n-hexane and 1-hexanol, explain the difference in Ar values of these substances based on their intermolecular forces Using the liquids, l-propanol and 2-propanol, explain the difference in based on their intermolecular forces values of these substances Which of the alcohols studied has: a. The strongest intermolecular forces of attraction b. The weakest intermolecular forces of attraction? c. Explain using the results of this experiment.

Explanation / Answer

Q1

methanol --> polar + hydrogen bonding --> those increase interamolecular forces and interaciton between molecules, so expec tmore energy requirement for breaking such interactions, Tboiling must be higher

n-heptane --> nonpolar, will only have van der waals / london dispersion forces present; therefore will have a very low BP

Q2

1-propanol and acetone:

acetone = polar only, no H-bonds present

1-propanol --> polar + Will form H-bonding with OH group, which is strongerinteraction

Therefore

BP of Acetone < BP 1-propanol

Q3

n-hexane --> alkane, no polarity, therefore only dispersion forces

1-hexanol --> polar + H-bonding present --> higher interaciotn, stronger forces present

Q4

1-propanol --> linear, more interacitons per unit surfac,e higher BP

2-propanol, branched , less area of interaciton, therefore, lower HP

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