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O GASES Solving for a gaseous reactant Combustion of hydrocarbons such as undeca

ID: 539942 • Letter: O

Question

O GASES Solving for a gaseous reactant Combustion of hydrocarbons such as undecane (Cul 124) produces carbon dioxide, a-greenhouse gas." Greenhouse gases in the Earth's atmosphere can trap the Sun's heat, raising the average temperature of the Earth. For this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide. 1. Write a balanced chemical equation, including physical state symbols, for the combustion of liquid undecane into gaseous carbon dioxide and gaseous water. 2. Suppose 0.190 kg of undecane are burned in air at a pressure of exactly 1 atm and a temperature of 16.0 °C. Calculate the volume of carbon dioxide gas that is produced. Be sure your answer has the correct number of significant digits. L.

Explanation / Answer

Q1

C11H24 + O2 = CO2 + H2O

balance C, H then O

C11H24 + O2 = 11CO2 + 12H2O

C11H24 + O2 = 11CO2 + H2O

C11H24 + 17O2 = 11CO2 + 12H2O

add phases

C11H24(l) + 17O2(g)= 11CO2(g) + 12H2O(g)

Q2.

m = 0.19 kg = 190 g of undecane

T = 16°C;

vind V of CO2

mol of undecane = mass/MW =190/156.3083 = 1.2155 mol of undecane

ratio is 1 mol of fuel = 11 mol of CO2

1.2155 mol of fuel = 11*1.2155 = 13.3705 mol of CO2

PV = nRT

V= nRT/P

V = (13.3705)(0.082)(16+273)/(1)

V = 316.85 L