58 B. A Study of a Mixture and Its Separation 1. Indicate whother oach substance

Question

58 B. A Study of a Mixture and Its Separation 1. Indicate whother oach substance below is solublo (S) or insoluble () in watar and 6 M HCI. Solvent White Sand Powdered Magnesium Sodium Chloride Carbon water 6 M HCI 2. Components of an unknown mixture Unknown mixture number: a. Observations upon evaporation of the water filtrate. b. Observations upon adding 6 M HCl to the residue on the filter paper. c. Conclusions: List component(s) present in the mixture. List component(s) not present in the mixture

Explanation / Answer

Q1.

white sand is not soluble in water, since those are minerals

carbon is not soluble in water

Magnesiuim is not likely to be soluble, actually, it is going to form a reaction

Mg(s) + 2H2O(l) --> Mg(OH)2 +H2(g)

sodium chloride -- >soluble inw ater

For acid:

white sand has Carbonates, such as Calcium carbonate, which will react with H+ ions to focm CO2(g)

pwdered carbon --> not likely to react, Carbon will appear to be inert

Magnesium + HCl --> expect H2(g) and basic solution formation, due to Mg(OH)2 production

NaCl --> HCl will have no effect, since Cl- is already present and Na+ remains in solution as Na+

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