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This is a Numeric Entry question/It is worth 3 points/You have 5 of 10 attempts remaining/There is no attempt penalty 30 Question (3 points) See page 1 6th attempt See Periodic Table See H A 30.1 mL sample of a H3PO4 (triprotic) solution is titrated with a 0.609 M NaOH solution. The equivalence point is reached when 50.1 mL of NaOH solution is added. What is the concentration of the H3PO4 solution? .37 5th attempt Feedback See Periodic Table See Hin A 30.1 mL sample of a H PO, (triprotic) solution is titrated with a 0.609 M NaoH solution The equivalence point is reached when 30/38 VIEW SOLUTION 32 OF 38

Explanation / Answer

Balanced chemical equation is:

3 NaOH + H3PO4 ---> Na3PO4 + 3 H2O

Here:

M(NaOH)=0.609 M

V(NaOH)=50.1 mL

V(H3PO4)=30.1 mL

According to balanced reaction:

1*number of mol of NaOH =3*number of mol of H3PO4

1*M(NaOH)*V(NaOH) =3*M(H3PO4)*V(H3PO4)

1*0.609*50.1 = 3*M(H3PO4)*30.1

M(H3PO4) = 0.338 M

Answer:  0.338 M

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