ollege-CHE 114-Fall17-DERI Activities and Due Dates Unit 9 Synthesis Homework 0

Question

ollege-CHE 114-Fall17-DERI Activities and Due Dates Unit 9 Synthesis Homework 0 10/15/2017 11:55 PM6/10 O 10/15/2017 08:51 PM -Print -d Periodic Table Calalator ncorrectIncorect Question 1 of 10 Sapling Learning Map For the reaction shown above, what is the chemical formula for the limiting reactant? NO Write the balanced chemical equation for the reaction, using lowest whole-number coefficients 2N0+2H2 2H2O+N, There is a hint available! View the hint by clicking on the dvider bar again to hide the hint Close @Previous Give up & View Solution Check ~owerNext Exit

Explanation / Answer

a)

according to the chemical equation 2 moles of water are needed to react 23 moles of O2

Therefore 1 moles of water require 11.5 moles of O2

X moles of water = 10 moles of O2

X = 1 x 10 /11.5 = 0.87 moles of water

b)

according to the chemical equation 2 moles of water produce 12 moles of HCl

that is 12x 36.46 (molar mass) =437.52 g of HCl

since 2 moles of water produce 437.52 g of HCl

one moles of water will produce 218.76 g of HCl

15.2 moles of water will produce = 218.76 x 15.2 = 3325.15 g of HCl

c)

according to the chemical equation when 12 moles of HCl is produced 24 moles of CO2 is also produced

therefore when 1 moles of HCl is produced 2 moles of CO2 will be produced.

76.5 g of HCL = 76.5/36.46 =2.09 moles of HCl

when 2.09 moles of HCl is produced 4.18 moles of CO2 will be produced (2.09x2= 4.18)

4.18 moles of CO2 = 4.18 x 44.01 (molar mass) = 183.96 g of CO2

d)

2 moles of C12H4Cl6 produces 24 moles of CO2

1 moles of C12H4Cl6 produces 12 moles of CO2

100.25/44.01 = 2.28 moles of CO2

X moles of C12H4Cl6 = 2.28 moles of CO2

X = 2.28/12 =0.19 Moles of C12H4Cl6

0.19 Moles of C12H4Cl6 = 360.87 x 0.19 = 68.56 g of  C12H4Cl6

e)

according to the chemical equation 12 moles of HCl is produced from 2 moles of C12H4Cl6

6 moles of HCl is produced from 1 moles of C12H4Cl6

2.5 kg of  C12H4Cl6 = 2500/360.87 = 6.92 moles of C12H4Cl6

6.92 moles of C12H4Cl6 will produce = 6.92 x 6 = 41. 56 moles of HCl

41.56 moles of HCl = 41.56 x 36.46 = 1515.50 g of HCl

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