substance gold gold gold gold marble marble10.0c marble final 0.30 0.30 g 0.30 g
ID: 541393 • Letter: S
Question
substance gold gold gold gold marble marble10.0c marble final 0.30 0.30 g 0.30 g 0.40 g 0.30 g 0.40 g 0.30 g 0.30 g 0.30 g 0.30 g 10.0 20.0 30.0 C 10,0 C 0,387 3 20.0C 30.0C 50.0C 20.0 C 20.0PC 20.0C 0.387 0.774 0.516 2.52 J 10.0 °C 20.0 30.0 30.0 50.0 3.36 J 2.52J 12.54 30.0°C water water water 40.0 50.0°C 30.0°C 25.08 J 25.08 a) As in question 1, determine a general formula that relates the different quantities. Again, you may need to define a new quantity, and you may determine your own symbols. What units does the new quantity have? b) Use your formula to determine the amount of heat needed to heat 3,25 g of marble from stc to 110°C. c) Use your formula to determine the final temperature after 20.00 J of energy are applied to 4.60 g of gold initially at 25.0°c..Explanation / Answer
(a)
The relation that suits for the given quantities,
Heat change, q = mass * specific heat * change in temperature
So, specific heat = 0.387 / (0.30 * 10.0) = 0.129 J/g.0C
(b)
q = 3.25 * 0.129 * (110 - 80)
q = 12.6 J
(c)
20.00 = 4.60 * 0.129 * (t2 - 25.0)
t2 - 25.0 = 33.7
t2 = 58.7 0C
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