answer of sodium hydroxide ure described in this module. The student added 100.0

Question

answer of sodium hydroxide ure described in this module. The student added 100.0 ml. of 0.8500M Nacotie acid, using perature-time data were collected S00M NaOl acid, usting the solutions, the following 3. The student then determined 1hvutam for the reaction procedure d 0.8404M acetic acid. Prior to and following the mixing of the acid and base solu time, temperature, c min temperature, C 7.52 17.54 17.55 17.57 17.58 time, HOAc 23.28 17.73 0.5 1.0 1.5 2.0 23.10 23.06 22.99 22.93 7.75 10 12 13 14 15 16 17 18 3.0 3.5 17.78 22.85 17.80 5.0 mixing 22.70 22.59 a) Plot the temperature-time data and determine the mean temperature of the unmixed reagents. (2) Determine AT from the graph answer

Explanation / Answer

Q1.

mean temperature for unmixed reagents ( T = 0 to T = 4.5)

Tmean = (17.55 + 17.77) /2 = 17.65 °C approx

Q2.

dT from graph,

Tmax --> 23.28

then..

dT = Tmax - Tinitial = 23.28 - 17.65 = 5.63°C

Q3

heat absorbed by mix:

Q = m*C*(Tf-Ti)

Q = (100+100)(4.184)(5.63)

Q = 4711.184 J

Q4

heat absorbed by calorimeter + thermometer +stirrer + using Ccal

Qsurroundings = Csurr * dT = Csurr * 5.63

substitute your value of Csurr (calcualted on question 2)=

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