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Question9 1 pts Give the individual reaction orders for all substances and the o

ID: 541955 • Letter: Q

Question

Question9 1 pts Give the individual reaction orders for all substances and the overall reaction order from this rate law: rate - k HNO2 order of HNO2 (input a number such as... -3, -2,-1, -0.75,.. 0.50 0 0.50,0.75... 1,2.. order of NO (input a number such as -3, -2, -1, .-0.75. -0.00.50 NO overall order (input a number such as.. -3, -2, -1,..-0.75,.. -0.50O..0.50, 0.75., 1,2,.2 By what factor does the rate change if the concentration of HNO2 is doubled input a number such as -3, -2,-1,..-0.75,.. -0.50.0.50, 0.75.., 1, 2.) By what factor does the rate change if the concentration of NO is doubled (input a number such as -3,-2,-1,..-0.75,.. -0.50 O...0.50, 0.75... 1, 2,.) By what factor does the rate change if the concentration of HNO2 is tripled and the concentration of NO is halved (input a number such as... -3, -2,-1, -0.75,. -0.50. O. 0.50, 0.75..., 1,2.)

Explanation / Answer

9)
a)
order of HNO2 = 4
This is power of HNO2 in rate law

b)
order of NO = -2
negative because NO is in denominator

c)
overall order = 4 + (-2) = 2


This is sum of all orders

d)
Order of HNO2 is 4
So, doubling concentration of HNO2, rate becomes 2^4 = 16 times
Answer: 16

e)
Order of NO is 2
So, doubling concentration of NO, rate becomes 2^(-2) = 1/4 times
Answer: 0.25

f)
tripling HNO2 will make order 3^4. = 81 times
halving NO will make order (1/2)^-2 = 4 times
So, overall effect on rate = 81*4 = 324 times

Answer: 324

Only 1 question at a time please

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