6. The following two experiments were conducted. The rate of the reactions were

Question

6. The following two experiments were conducted. The rate of the reactions were measured and the follwing two rates were obtained, rate-H = 6.7 x 100 mol/s and rate.): 1 x 108 mol/s. a) Calculate the kinetic isotope effect (KIE) for this elimination reaction. b) What does the KIE tell you in this case? 7. The following two experiments were conducted. The rate of the reactions were measured and the follwing two rates were obtained, rate-H = 2.8 x 105 mol/s and rate-D-2 x 105 mol/s a) Calculate the kinetic isotope effect (KIE) for this elimination reaction. b) What does the KIE tell you in this case? Br H20 Br .H2O heat D' D 8. Explain why the stability order is (CH:) C CHs CH2-CH-CH2.

Explanation / Answer

Answer 6 (a) Kinetic Isotope effect = KH / KD

KH = rate constant-H = 6.7 *108 mol/s and KD = rate constant-D = 1* 108 mol/s

  Kinetic Isotope effect = KH / KD = (6.7 *108 mol/s)/(1* 108 mol/s) = 6.7

Kinetic Isotope effect = KH / KD = 6.7 for this elimination reaction

(b) This Value .i.e.   Kinetic Isotope effect = KH / KD = 6.7 tells about the Normal Isotope effect in which   Kinetic Isotope effect value is greater than one.

Answer 7 (a)

Kinetic Isotope effect = KH / KD

KH = rate constant-H = 2.8 *105 mol/s and KD = rate constant-D = 2* 105 mol/s

  Kinetic Isotope effect = KH / KD = (2.8*105 mol/s)/(2* 105 mol/s) = 1.4

Kinetic Isotope effect = KH / KD = 1.4 for this elimination reaction

(b) This Value .i.e.   Kinetic Isotope effect = KH / KD = 1.4 tells about the Heavy atom isotope effects which involves the substitution of carbon, nitrogen, sulfur, oxygen, and bromine, with effects that are much smaller as value between 1.02 and 1.10.

Answer 8 The stability order because of the presence of bulky group which causes the stearic hindrances.

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