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Q56. Deep sea vents are openings in the sea floor where hot water and nutrients

ID: 54216 • Letter: Q

Question

Q56. Deep sea vents are openings in the sea floor where hot water and nutrients spew out. As shown to the right, they have a rich community of species. However, individual vents often become plugged up, while new vents can appear in far flung parts of the ocean. You would expect to find that species who specialize at living around these vents are especially good at:
A.Dispersal
B. Intrinsic growth
C. Local extinctions
D. Patch occupancy


Q57. Approximately what patch occupancy, P, would you expect for a metapopulation at equilibrium with a colonization rate of 1.5 and an extinction rate of 0.6? (Hint: You can calculate the answer using a graph earlier in this section.)

Q58. Roads often decrease dispersal rates for animals and can divide patches in two. How might these consequences of building roads affect the survival of a metapopulation?
A.Roads should generally increase metapopulation survival by dividing patches and thereby creating more potential populations.
B. Roads should generally increase metapopulation survival by reducing dispersal, which increases survival of individual patches.
C.Roads should generally decrease metapopulation survival by reducing dispersal, which decreases recolonization of patches.
D.Roads should generally decrease metapopulation survival by dividing patches, which increases immigration rates.


Q59. For many years, the conservation community debated whether, with a given amount of funding, it would be better to conserve one large patch of land or several smaller patches. Describe situations in which each of those options might be better, justifying your answer based on metapopulation dynamics.

Explanation / Answer

Answer 56- Option A
Since the species have to go to a far awar location for nutrients, they have to be good in dispersal. This way they could support their survival.

Answer 57-

The formula for this would be -
k = 1 - extinction rate / colonization rate = 1 - 0.6/1.5 = 1- 0.4 = 0.6.

Answer 58- Option B

Since there are roads, the dispersal rates will decrease. The animals won't be able to reach out from their niche and thus create an isolated patch. This will create numerous patches supporting metapopulation and animals will tend to increase in their respective patches.