t-lab Questions he all calculations, show all work and the unrounded answer. Wri

Question

t-lab Questions he all calculations, show all work and the unrounded answer. Write the final answer (rounded the rules for significant figures) on the blank provided. Re-write the balanced reaction for the decomposition of hydrogen peroxide. How does the experimentally determined mole ratio correlate with the ratio of the coefficients in this balanced reaction? Potassium chlorate decomposes to potassium chloride and molecular oxygen. Write the balanced equation and calculate the volume of molecular oxygen expected to form when 0.126 grams of potassium chlorate decompose at 24.2 C and 745.8 mmHg of dry gas pressure 71

Explanation / Answer

Q1.

decomposition of hydrogen peroxide

H2O2 will form H2O (water) and Oxygen gas O2g

balance

H2O2(aq) = H2O(l) + 1/2O2(g)

also expressed as

2H2O2(aq) = 2H2O(l) + O2(g)

Q2.

mole ratio correleate the ratio of coefficients...

We will have to relate

2 mol of peroxide = 2 mol of water

and

2 mol of peroxide = 1 mol of Oxygen

as well as

2 mol of water = 1 mol of oxygen

Q3

KClO3 --> KCl + O2(g)

balance

KClO3 --> KCl + 3/2O2(g)

m = 0.126 g of KClO3

mol of KClO3 = mass/MW = 0.126/122.55 = 0.001028 mol of KClO3

this produces

3/2 mol of O2 = 3/2*0.001028 = 0.001542 mol of O2

now..

PV = nRT

V = nRT/P

V = (0.001542)(62.4)(24.2+273.15)/(745.8)

V = 0.038363 L

V = 0.038363*10^3 mL = 38.36 mL of O2

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.