Eq 487 Determining the Common lon Effect on the n Tartrate Purpose: Determine th
ID: 542846 • Letter: E
Question
Eq 487 Determining the Common lon Effect on the n Tartrate Purpose: Determine the solubility of potassium varying the amount of sodium and be calculated from these solutions. n squeous solutions The solubility product for KHT will Background Information: romequilibrium and solubility discussions, we learned about solubility products and the common ion effect. If a system is at on is added to the it will the salt to become more or less soluble. Wil it change uilibrium constant Canbe cal cvlaled us! Checklist: > Prepare KHT solution > Setup filtering apparatus and filter your KT-NaCl KCI solution s soc ía on Determine temperature of filtrate sample (saturated KHT solution)at cemp avrAkth > Prepare titration apparatus >Titrat te filtrate sample with standardized NaOH solution Hazards: Phenolphthalein solution flammable and toxic Potassium chloride - irritant Sodium chloride irritant Sodium hydroxide toxic and corrosive Any solutions in lab potentially can be corrosive or an iritant 2.150 L 3,100mL j.c Procedure: of saturated KHT-NaC-K 1. Weigh approximately 1.9-2.1g of KHT powder into a clean 150mL beaker, Use a nLakh magnetic Tefion ker to stir 2. Your instructor wil our instructor will ssign or have you sign up for a solution to prepare based on the table below 2- z.ooa3 Table 1 Solution volume of 0.10M volume of 0.10M 100.0 0.0 10.0 20.0 30.0 40.0 50.0 60.0 70.0 80.0 90.0 0.090 0.080 0.070 0.060 0.050 0.040 0.030 0.020 0.010 0.020 0.030 0.040 0.050 0.060 0.070 0.080 0.090 3 80.0 70.0 60.0 50.0 40.0 30.0 20.0 10.0 10 F17Explanation / Answer
4) there will be very less effect if we use NaBr-KBr instead of NaCl-KCl. We may observe a slight decrese in the solubility .
5)
Ksp = [K+][HT-]
[K+] = [HT-] = solubility of KHT = 0.8530 g /100mL = 8.530 g / 100mL = 8.530 g / L
Ksp = 8.530 X 8.530 = 72.76
the mass of KHT dissolved = 21.50g / L
Solubility will be = 8.530g / L
so the amount remained undissolved =21.50 - 8.530 = 12.97 grams
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