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-ac Replace 11 List Para Styles Calculate molarity HC2H302 , | 2-B . | | 1 Norma

ID: 542968 • Letter: #

Question

-ac Replace 11 List Para Styles Calculate molarity HC2H302 , | 2-B . | | 1 Normal Select Editing ph c. d. Grams HC2Hs0:2 3. How would you prepare 300 ml of a 0.6M solution from a 4M stock solution? (2 points) Explain why it is important to boil the water first that is used to make NaOH solution that was standardized? (2 points) 4. 5. A student recorded the following data for the alcohol content of a blood sample:96 C2HsOH: 0.084, 0.068, and 0.079. Calculate the 95% confidence limit for the average of this data. (2 points) EXPERIMENTS IN GENERAL GHMISTRY horh Peer Corell and Richand Fond

Explanation / Answer

5) The individual alcohol content values are given; find the average and the standard deviation as below.

x (%)

0.084

0.068

0.079

x (%)

1/3*(0.084 + 0.068 + 0.079) = 0.077

(Standard Deviation, %) = (x - x)2/(n – 1) [n = number of measurements]

[(0.084 – 0.077)2 + (0.068 – 0.077)2 + (0.079 – 0.077)2]/(3-1) = 0.008185

Z* value

1.96

Margin of error (Z*X/n) (%)

1.96*(0.008185/3) = 0.009262 0.0093

Confidence interval at 95% CL = x Z*X/n

0.0770.00926 0.077 0.0093

x (%)

0.084

0.068

0.079

x (%)

1/3*(0.084 + 0.068 + 0.079) = 0.077

(Standard Deviation, %) = (x - x)2/(n – 1) [n = number of measurements]

[(0.084 – 0.077)2 + (0.068 – 0.077)2 + (0.079 – 0.077)2]/(3-1) = 0.008185

Z* value

1.96

Margin of error (Z*X/n) (%)

1.96*(0.008185/3) = 0.009262 0.0093

Confidence interval at 95% CL = x Z*X/n

0.0770.00926 0.077 0.0093