THERE IS NO OTHER INFORMATION GIVEN BESIDES 298K Exercise 19.87 The following re

Question

THERE IS NO OTHER INFORMATION GIVEN BESIDES 298K

Exercise 19.87

The following reactions are important ones in catalytic converters in automobiles. Calculate Gfor each at 298 K. Predict the effect of increasing temperature on the magnitude of G.

Part A

2CO(g)+2NO(g)N2(g)+2CO2(g)

Express your answer using four significant figures.

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Part B

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Part C

5H2(g)+2NO(g)2NH3(g)+2H2O(g)

Express your answer using four significant figures.

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Part D

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Part E

2H2(g)+2NO(g)N2(g)+2H2O(g)

Express your answer using four significant figures.

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Part F

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Part G

2NH3(g)+2O2(g)N2O(g)+3H2O(g)

Express your answer using four significant figures.

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Part H

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Exercise 19.87

The following reactions are important ones in catalytic converters in automobiles. Calculate Gfor each at 298 K. Predict the effect of increasing temperature on the magnitude of G.

Part A

2CO(g)+2NO(g)N2(g)+2CO2(g)

Express your answer using four significant figures.

Grxn =   kJ  

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Part B

G will increase with increasing temperature. G will decrease with increasing temperature.

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Part C

5H2(g)+2NO(g)2NH3(g)+2H2O(g)

Express your answer using four significant figures.

Grxn =   kJ  

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Part D

G will increase with increasing temperature. G will decrease with increasing temperature.

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Part E

2H2(g)+2NO(g)N2(g)+2H2O(g)

Express your answer using four significant figures.

Grxn =   kJ  

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Part F

G will increase with increasing temperature. G will decrease with increasing temperature.

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Part G

2NH3(g)+2O2(g)N2O(g)+3H2O(g)

Express your answer using four significant figures.

Grxn =   kJ  

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Part H

G will increase with increasing temperature. G will decrease with increasing temperature.

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Explanation / Answer

Part A : 2CO(g)+2NO(g)N2(g)+2CO2(g) : Gorxn = ?

Gorxn = G0fproducts – G0freactants

Gorxn = [(G0fN2(g) )+ (2 x G0fCO2 (g) )]- [( 2 x G0fCO(g) )+ (2 x G0fNO (g) )]

= [(0)+(2x(-394.4))] - [(2x(-137.3))+ (2x(86.6))] kJ/mol

= -687.4 kJ

Part B : Since Gorxn is negative upon increase in temperature Gorxn also increases

Part C : 5H2(g)+2NO(g)2NH3(g)+2H2O(g) : Gorxn = ?

Gorxn = G0f  products – G0f  reactants

Gorxn = [(2xG0f  NH3(g) )+ (2 x G0f  H2O (g) )]- [( 5x G0fH2(g) )+ (2 x G0f  NO (g) )]

= [(2x(-16.5))+(2x(-228.6))] - [(5x0)+ (2x(86.6))] kJ/mol

= -663.4 kJ

Part D : Since Gorxn is negative upon increase in temperature Gorxn also increases

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