E 3 on 3 5. (60 pts) Chemical Equilibrium () A 0.100 M 5asolution of N204 was pl
ID: 544277 • Letter: E
Question
E 3 on 3 5. (60 pts) Chemical Equilibrium () A 0.100 M 5asolution of N204 was placed in a spectrophotometer. The spectrophotometer - 1 2 T Lun. was set to measure the absorption due to product NO2 produced by the reaction.NOa(9) S 2NO2(g) The concentration of NO, was determined after one minute and then each for 23 minutes. A graph of these concentrations (Y = NO2) is shown. Determine the minute thereafter equilibrium constant for this reaction. Concentration of Y vs. Time 2 0.060 8 0.040 8 0.020 0 510 16 25 Time, minutesExplanation / Answer
Keq = [NO]^2 /[N2O4]
in equilbirium
get
[N2O4] = 0.1
[NO] = 0
in equilbirium
[N2O4] = 0.1 - x
[NO] = 0 + 2x
and from the graph
[NO] = 0 + 2x = 0.06
then, x = 0.06/2 = 0.03
[N2O4] = 0.1 - x = 0.10-0.03 = 0.07
get
Keq = [NO]^2 /[N2O4]
Keq = (0.06^2 ) /0.07
Keq = 0.0514
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