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E 3 on 3 5. (60 pts) Chemical Equilibrium () A 0.100 M 5asolution of N204 was pl

ID: 544277 • Letter: E

Question

E 3 on 3 5. (60 pts) Chemical Equilibrium () A 0.100 M 5asolution of N204 was placed in a spectrophotometer. The spectrophotometer - 1 2 T Lun. was set to measure the absorption due to product NO2 produced by the reaction.NOa(9) S 2NO2(g) The concentration of NO, was determined after one minute and then each for 23 minutes. A graph of these concentrations (Y = NO2) is shown. Determine the minute thereafter equilibrium constant for this reaction. Concentration of Y vs. Time 2 0.060 8 0.040 8 0.020 0 510 16 25 Time, minutes

Explanation / Answer

Keq = [NO]^2 /[N2O4]

in equilbirium

get

[N2O4] = 0.1

[NO] = 0

in equilbirium

[N2O4] = 0.1 - x

[NO] = 0 + 2x

and from the graph

[NO] = 0 + 2x = 0.06

then, x = 0.06/2 = 0.03

[N2O4] = 0.1 - x = 0.10-0.03 = 0.07

get

Keq = [NO]^2 /[N2O4]

Keq = (0.06^2 ) /0.07

Keq = 0.0514