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Question

e chegg Study I Guided . G chegg Study | Guided x x 2 LON-CAPA Molarity,x LON-CAPA Stoichiomet ernst chem st care a: x G Lesson . Chegg Tutc +/X add%2f e Volunteer-Maple cturelset 2stestoch poblem?symbul %2f9 318 stu artofsaunaca c ? https atcel chem 1 1 1/problem volunteer-Northe 2 Messages Courses Help Logout BC SPCA: BC SP CA Course Hero db Vancouver Aquariur m e) User Dashboard E zmbr Chem110-111 2017-3 Lecture Sohyun Ohe (Student -section : D 100) Main Menu Contents Grades Syllabus Assignment 5. O Timer Notes à Evaluate-Feedback-print einfo Course Contents » .. Stoichiometry of a Two Step Process Due in 39 minutes 2 homework point(s) Stoichiometry of a Two Step Process Consider the following two-step reaction sequence P4 + 502 2P205 en generated in the first step is consumed in the second step, what mass of KCIO3 is needed in the first step to produce 50.2 g of P2os in the second step? Submit Answer Tries 0/10 Send Feedback Post Discussion 2017-10-214 Backs

Explanation / Answer

P4 + 5O2 ---------------> 2P2O5

2.5 mmol of oxygen requried to form 1mmol of phosphors pentoxide

80 g (2.5 mmol) of oxygen requied to form 142 g of P2O5 (1 mmol)

50.2 g of P2O5 required oxygen is obtained by

80 g = 142 g

50.2 = ?

cross multipling

80 x 50.2 / 142 = 28.28 g of oxygen requied

2KClO3 --------------> 2KCl + 3O2

1 mmol of KClO3 will give 1.5 mmol of oxygen molecule

that is 122.55 g of KClO3 give 48 g of oxygen

then 28.28 g of requied how much KClO3

122.55 = 48 g

? = 28.28

cross multipling

28.28 x 122.55 / 48 = 72.20 g of KClO3

therefore 50.2 g of P2O5 required 72.20 g of KClO3

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