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cause Home mistry.com/myct/itemView?asagnmentProblemiD-83493990 previous| 10 of 15 net a My cot Course Exercise 16.40 Part A a solution that is 0.140 Min propanoic acid and 0.125 Min potassium propancate Express your answe using two decimal places. Sylabu Use the Henderson-Hasselbalch equation to calculate the pH of each solution etext pH Submit My Answers Gve Up user Part B a solution that contains a 685% all, N by mass and 0 840% CL, NIla by mass Express your answer using two decimal places pH 59 P O 220 Submit My Answers Give U ment

Explanation / Answer

16.40.

Part-A

Propanoic acid = 0.140M

Sodium propionate =0.125M

ka of propanoic acid= 1.34x 10^-5

-log(Ka) = -log(1.34x10^-5)

PKa = 4.87

PH = PKa + log[salt/acid]

     PH= 4.87 + log[0.125/0.140]

          = 4.82

PH = 4.82.

Part-b

C6H5N = 0.685%

C6H5NHCl = 0.840%

PKb of PYridine= 8.75

POH = 8.75+log[0.840/0.685]

       = 8.84

PH = 14-POH = 14-8.84 =5.16

PH= 5.16

Part-c

mass of HF=12.0grams

Molar mass of HF= 20grams

number of moles = 12/20 = 0.6mole

mass of NaF = 24 grams

molar mass of NaF = 42 grams

number of moles of NaF = 24/42 == 0.57mole

PKa Of HF= 3.17

PH = 3.17+log[0.57/0.6]

     = 3.14

PH= 3.14.

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