salt bridge Pb SOA Ag NO 3 Pb+2 + 2e. Pb(s) Ag+ + le. Ag(s) E.-013V E. +0.30V Pb

Question

salt bridge Pb SOA Ag NO 3 Pb+2 + 2e. Pb(s) Ag+ + le. Ag(s) E.-013V E. +0.30V Pb(s)l Pb2+ (1M) I Ag+ (1M) I Ag(s) Determine which of the following statements about the cell shown are True or False FalseThe cell, as represented by the line notation, is a voltaic cell. True The mass of the lead electrode is increasing True As the reaction proceeds, the concentration of the lead ions decreases FalseElectrons are spontaneously produced in the lead half-cell True The silver electrode is the anode False The silver half-cell is the anode True Anions move to the lead half-cell False . The standard cell potential, Decide which reaction is the oxidation half-reaction and which is the reduction reaction. Then look at the reactants and products of these two reactions. Products will be produces and reactants consumed during the reaction. Oxidation occurs at the anode and eduction occurs at the cathode Oxidation reactions produce electrons. Reduction reactions consume electrons , equals 0.93 V

Explanation / Answer

(i) True , cell is voltaic cell because it produces emf.

(II) False, because Pb acts as anode get corroded.

(iii) False, because Pb (s) is oxidised in Pb+2 so ion get increases with time.

(iv) True, because Pb get oxidised by lossing 2 electrons.

(v) False, becausesilver electrode get reduced, acts as cathode.

(vi) False, because it undero reduction acts as cathode.

(vii) False because anion moves at silver as it get reduced.

(VIII) E cell = E °cathode - E ° anode

= .80V -(-.13V)

= .93V

True

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