Common-lon Effect on Solubility for a Metal Hydroxide The generic metal hydroxid

Question

Common-lon Effect on Solubility for a Metal Hydroxide The generic metal hydroxide M (OH) 2 has Kap-7.85x 10-18 Consider the dissolution of AB(s) Part A AB(s) A (aq) B (aq) Le Châtelier's principle tells us that an increase in either Aor B] will shift this equilibrium to the left, reducing the solubility of What is the solubility of M(OH2 n pure water? Express the molar solubility numerically using three significant figures. In other words, AB is more soluble in pure water than in a solution that already contains A or B ions. This is an example of the common-ion effect Hints 0.58113 106 Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining Part B What is the solubility of M(OH2 in a 0.202 M solution of M(NOs)2? Express the molar solubility numerically using three significant figures Hints 2.5.109 Submit My Answers Give Up Incorrect; Try Again; 5 attempts remaining

Explanation / Answer

M(OH)2 <====> M2+(aq) + 2 OH- (aq)

Ksp = [M2+][OH-]2

Ksp = S * (2S)2

Ksp = 4S3

S = solubility

S = [Ksp/4]1/3

Part A

Solubility M(OH)2 in pure water = [7.85*10-18/4]1/3

S = [1.9625*10-18]1/3

S = 1.25*10-6 M

part B

Ksp = [M2+][OH-]2

Ksp = [0.202][OH-]2

[0.202][2S]2 = 7.85*10-18

S2 = 7.85*10-18 / (0.202 * 4)

S2 = 9.715*10-18

S = 3.11*10-9 M

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