4. How many grams of magnesium nitride is needed to react with an excess amoun p

Question

4. How many grams of magnesium nitride is needed to react with an excess amoun potassium oxide to produce 11.6 grams of magnesium oxide? Use the following to answer questions 5-8 5. 32 grams of propane (Cll) is burned in water? excess oxygen gas to produce how many grams of 6. How many grams of oxygen gas is needed to make 30 grams of carbon dioxide? 7. If 0.45 grams of water is formed during the combustion of propane, how many grams of carbon dioxide is formed? Theoretical Vielto your soich problem experimental yield 8. How many grams of propane, Ci, are needed to make 1-40amauf-yler lh the peoblom or the SOTEL %Yield _ _actualield 1100 Theoretical Yeild l) Balance the equation for the reaction of iron (U1) phosphatle with sodium sulfate to make ron (III) sulfate and sodium phosphate 25 grams of iron (IIl) phosphate and an excess of sodium IfI perform this reaction with sulfate, how many grams of iron (III) sulfate can I make? a)

Explanation / Answer

4.

Balanced Chemical equation is

Mg3N2 +3 K2O give 3MgO + 2K3N

Given that Mg3N2 is the limiting reagent.

Molar mass of Mg3N2: 100.9 g/mol

Mass of Mg3N2 = ?

Molar mass of MgO = 40.3 g/mol

Number of moles of MgO = mass/molar mass = 11.6/40.3 = 0.28784 moles

As per the balanced chemical equation, one mole of MgO is formed from 1/3 moles of Mg3N2

Thus number of moles of Mg3N2 = 1/3 x 0.28784 = 0.09594 moles

Mass of Mg3N2 = number of moles x molar mass = 0.09594 x 100.9 = 9.681 g

As per the policy of Chegg, only one question is answered

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