2.Experimental Procedure, Parts A.4, 5 a. When a metal at a higher temperature i
ID: 546377 • Letter: 2
Question
2.Experimental Procedure, Parts A.4, 5 a. When a metal at a higher temperature is transferred to water at a lower temperature, heat is inevitably lost to the calorimeter (Figure 25.4). Will this unmeasured heat loss increase or decrease the calculated value of the specific heat of the metal? Explain. See equation 25.5. b. Explain why the extrapolated temperature is used to determine the maximum temperature of the mixture rather than the highest recorded temperature in the experiment. See Figure 25.5.Explanation / Answer
Q2a
for the metal, we will have the next balance
Qmetal = Qliquid
if there is a loss:
Qloss + Qmetal = Qliquid
Qmetal = Qliquid - Qloss
therefore, (Qliquid - Qloss) is lower
meaning that
Qmetal will be calcualted LOWER
Qmetal = mmetal * Cp metal ¨(Tf-Tmetal)
if Tf, Tmeta lare fixed, and mass of metal won't change
then Cp metal must decrease
meaning that the Cp clacualted will be LOWER is there is any heat loss
b)
extrapolation is needed when we do NOT have values/constants/data on the range given
we avoid the "highest" temperature, since it is not reliable due to the thermometer calibration
it is much better to "extrapolate" specially if there is no data present
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