Please complete the following reactions, and show the total ionie and net ionic

Question

Please complete the following reactions, and show the total ionie and net ionic forms of the equation: 6. KPOdaq) + Al(NO)(aq) 7, Bel,(aq) + Cu,so.(aq) 8. Ni(NO3)(aq) + KBr(aq) 9, cobalt(III)bromide + potassium sulfide 10, barium nitrate + ammonium phosphate 11, calcium hydroxide + iron(III)chloride 12, rubidium fluoride + copper(II)sulfate Solubility Rules 1. All salts of Group IA, and ammonium are soluble. 2. All salts of nitrates, chlorates and acetates are soluble 3. All salts of halides are soluble except those of silver), copper(), lead(II), and mercury(). 4. All salts of sulfate are soluble except for barium sulfate, lead(II) sulfate, and strontium sulfate 5. All salts of carbonate, phosphate and sulfite are insoluble, except for those of group IA and ammoniun 6. All oxides and hydroxides are insoluble except for those of group IA, caleium, strontium and barium. 7. All salts of sulfides and insoluble except for those of Group IA and IIA elements and of ammonium pag

Explanation / Answer

Ans 6 :

The balanced molecular reaction will be :

K3PO4 + Al(NO3)3 = AlPO4 + 3KNO3

The ionic equation is given as :

3K+ (aq) + PO43- (aq) + Al3+ (aq) + 3NO3- (aq) = AlPO4 (s) + 3K+ (aq) + 3NO3- (aq)

The net ionic equation can be obtained by cancelling out the spectator ions from the ionic equation.

So the net ionic equation is given as :

Al3+ (aq) + PO43- (aq) = AlPO4 (s)

Related Questions

Navigate

• Browse (All)
• Browse P
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.