Ava Organic Chemistry Roberts & Company Publishers preserted by Sapling Learning

Question

Ava Organic Chemistry Roberts & Company Publishers preserted by Sapling Learning The standard free energy of activation of a reaction A is 78.7 kJ mor1 (18.8 kcal mol-') at 298 K. Reaction 8 reaction A at the same temperature. The products of each reaction are 10.0 KJ mol (2.39 kcal mol") more stable than the reactants (a) What is the standard free energy of activation of reaction B You ca kJ mol give up (b) What is the standard free energy of activation of th You can kJ mol" answer in attempt a kI mol O Help With O Web Help &

Explanation / Answer

a)

if B = 10^6 x faster than a

rate B /rate A = 10^6

kb/ka = exp(-(-Ea + Eb) /(RT))

10^6 = exp(78700 -+ Eb ) /(8.314*298))

ln(10^6) * (8.314*298) = 78700 - Eb

-Eb = ln(10^6) * (8.314*298) - 78700

Eb = 44471.0778759

Eb = 44.471 kJ/mol

b)

find reverse of A

Ea = Eaforward + Eareverse = 78.7 + 10 = 88.7 kJ/mo

c)

for reverse B

Eb = Ebforward + Ebreverse = 44.471 + 10 = 54.471 kJ/mol

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