1. Give the conjugate base of each of the following: HSO3 ; HCOj ; H20; 2. Give
ID: 546711 • Letter: 1
Question
1. Give the conjugate base of each of the following: HSO3 ; HCOj ; H20; 2. Give the conjugate acid of each of the following: so ;cof H2O oH: 3. For each of the following reactions: H2SO4(aq) + H2 H3O+(aq) + HSO (aq) HS04 (aq) + H2O Sog(aq) + H3O+(aq) H2O + H2O H3O+(aq) + OH-(aq) HCN(aq) + CO2-(aq) HCO3 (aq) + CN-(aq) H2S(g) + NH3(E) HS-(am) + NH4+(am) (am iii) iv) v) )- dissolved in liquid ammonia a) Which reactant is the acid? b) Which reactant is the base? c) Find the two conjugate pairs present in the reaction. mmonia can react as an acid or a base. a) What is the conjugate acid of ammonia? b) What is the conjugate base of ammonia? c) Complete the following acid-base reaction in which NH3(0) acts as both an acid and a base: NH3(1) + NH3(1) Complete the following table of conjugate acids and bases: 5. Acid Base H2S S2- NO2 H3PO4 OCN H30+ OH F- HPO42- HOCIExplanation / Answer
1. Conjugate base is obtained by the removal of one proton from the given species.
HSO4- : SO42-
HCO3- : CO32-
H2O : OH-
OH- : O2-
H3O+ : H2O
NH4+ : NH3
CH3NH3+ : CH3NH2
HF : F-
CH3COOH : CH3COO-
2.
Cojugate acid is obtained by adding a proton to the given species.
SO42- : HSO4-
CO32- : HCO3-
OH- : H2O
H2O : H3O+
O2- : OH-
NH3 : NH4+
CH3NH2 : CH3NH3+
CN- : HCN
CH3COO- : CH3COOH
F- : HF
HCO3- : H2CO3
NH2- : NH3
3.
(i)
Acid : H2SO4
Base: H2O
Conjugate acid - base pairs: H2SO4, HSO4- and H2O, H3O+
(ii)
Acid : HSO4-
Base: H2O
Conjugate acid base pairs: HSO4-, SO42- and H2O, H3O+
(iii)
Acid : H2O
Base : H2O
Conjugate acid base pairs : H2O, H3O+ and H2O, OH-
(iv)
Acid: HCN
Base: CO32-
Conjugate acid - base pairs : HCN, CN- and CO32-, HCO3-
(v)
Acid: H2S
Base: NH3
Conjugate acid - base pairs : H2S, HS- and NH3, NH4+
4.
(a) Conjugate acid of ammonia : NH4+
(b) Conjugate base of ammonia : NH2-
NH3 + NH3 ----------> NH4+ + NH2-
5.
H2S : HS-
HS- : S2-
HNO2 : NO2-
H3PO4 : H2PO4-
HOCN : OCN-
H3O+ : H2O
OH- : O2-
HF : F-
H2PO4- : HPO42-
HOCl : OCl-
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