Help me finish my assignment all the way please! Buffer Solutions 1: ( point) Wh

Question

Help me finish my assignment all the way please!

Buffer Solutions 1: ( point) What was the observed value of the pH of the acetate buffer solution? (I point) Fill in the meastred pH and the calculated [Hl, pOH and [OHr] values for each of the experiments designed to examine the effects of added acids and bases on buffers. 2. Measured pH Calculated [H] Calculated pOH Calculated [OH] Beaker 1 (buffer + acid) I-1 Beaker 2 (buffer + base) . (o Beaker 314 (water + acid) Beaker 412.5 (water + base) :12. 3.18 3. (I point) Show your calculation of [H], poH and [OH] for Beaker 1:

Explanation / Answer

2.

Beaker 1

(buffer + acid)

Beaker 2

(Buffer + base)

Beaker 3

(water + acid)

Beaker 4

(water + base)

Note: pH = -Log[H+], i.e. [H+] = 10-pH

pH + pOH = 14

Similarly pOH = -Log[OH-], i.e. [OH-] = 10-pOH

3.

Note: [H+] = 10-pH

Ka = c[H+]2/Kw, where Kw = ionic product of water = 10-14 and c = concentration of salt

[H+][OH-] = 10-14 then you can find [OH-]

Similarly, Kb = c[OH-]2/Kw

For acetic acid, i.e. HCH3CO2, Ka = [H+]2/c, where c = given concentration of acid

By using the above formulae, you can complete the table.

Measured pH Calculated [H+] Measured pOH Calculated [OH-]

Beaker 1

(buffer + acid)

3.78 10-3.78 = 1.66*10-4 M 14 - 3.78 = 10.22 10-10.22 = 6.03*10-11 M

Beaker 2

(Buffer + base)

5.6 10-5.6 = 2.51*10-6 M 14 - 5.6 = 8.4 10-8.4 = 3.98*10-9 M

Beaker 3

(water + acid)

1.14 10-1.14 = 7.24*10-2 M 14 - 1.14 = 12.86 10-12.86 = 1.38*10-13 M

Beaker 4

(water + base)

12.51 10-12.51 = 3.09*10-13 M 14 - 12.51 = 1.49 10-1.49 = 3.24*10-2 M

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