.14 How many milliliters of water must be added to 265 mL of a 1.75 M HCl soluti

Question

.14 How many milliliters of water must be added to 265 mL of a 1.75 M HCl solution to dilute it to 0.750 M, assuming the volumes are additive? A. 353 mL B. 114 mL C. 202 mL D. 618 mL .14 How many milliliters of water must be added to 265 mL of a 1.75 M HCl solution to dilute it to 0.750 M, assuming the volumes are additive? A. 353 mL B. 114 mL C. 202 mL D. 618 mL .14 How many milliliters of water must be added to 265 mL of a 1.75 M HCl solution to dilute it to 0.750 M, assuming the volumes are additive? A. 353 mL B. 114 mL C. 202 mL D. 618 mL

Explanation / Answer

We can use the following relationship for volume and molarity.

V1S1 = V2S2

Where V= volume, S=molarity, 1 for initial and 2 for final.

Now, we can write,

V1= 265 ml, S1 = 1.75 M

V2 = ? S2 = 0.750

So, V2 = 265*1.75/0.750 ml = 618 ml is the final volume.

So water to be added = 618 -265 = 353 ml.

Therefore,

A. is the answer.

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