In the first part of this exercise we determine the calorimeter constant, Ccal W

Question

In the first part of this exercise we determine the calorimeter constant, Ccal We measure the temperatures of samples of cold and hot water for several minutes. At 3.0 minutes, we mix the water samples and follow the temperature of the resultant mixture for 7 minutes. The hot and cold water temperatures are extrapolated forward to the time of mixing (3 minutes). The temperature of the mixture at the time of mixing (3 min) is extrapolated backward from the data. We do this graphically. The cold water is initially in the calorimeter and therefore the calorimeter undergoes the same temperature change as the cold water A graph showing the idealized behavior of the system is shown below. The temperature axis is intentionally unlabeled and the data relevant to the determination of the calorimeter constant are in the table below the graph.

Explanation / Answer

1. If the system was ideal, temperature after mixing would be as follows

Tf = ((Tc * Vc)+(Th * Vh))/(Vc + Vh)

Tc is temp of cold stream at mixing; Th is temp of hot stream at mixing

Vc and Vh are volumes of the two streams respectively. Tf is temperature after mixing in case of ideal system

Tf = ((17.3*48.6)+(54.7*48.1))/(48.6+48.1) = (840.78+2631.07)/96.7 = 3471.85/96.7 = 35.903 C

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