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100% , Wed 12:17 PM Chrome File Edit View History Bookmarks People Window Help O

ID: 547787 • Letter: 1

Question

100% , Wed 12:17 PM Chrome File Edit View History Bookmarks People Window Help O * Quiz: Thermodynamics 2 e chegg Study l Guided Solutio × Assessment 7-Assessment 7 × Secure https://ufl.instructure.com/courses/342 794/quizzes/569739/take Kendall UF Question 8 0.33 pts FLORIDA Calculate the equilibrium constant Keq for the following reaction at 25°C. Account (S° values in J/mol K: N2(g), 191.5; O2(g), 205.0; Cl2(g), 223.0; NOCI(g), 261.6) Dashboard N2(g) + O2(g) + Cl2(g) 2 NOCl(g) 4° = 103.4 kJ Courses 28 Groups 5.91 x 10-17 6.99 x 1024 2.43 x 10-20 2.01 x 10-10 8.82 x 10-29 Calendar Inbox Help D Question 9 0.33 pts 25

Explanation / Answer

Recall that

dG = -RT*ln(K)

then

K = exp(-dG/(RT))

now..

dG = dH - T*dS

dG = 103.4*10^3 - 298*(dS)

dS = Sproducts - Sreactants = 2*261.6 - (191.5 + 205+ 223)= -96.3

dG = 103.4*10^3 - 298*(-96.3)

DG = 132097.4 J/mol

substitute

K = exp(-dG/(RT))

K = exp(-132097.4 /(8.314*298))

K = 6.991*10^-24

choose B, 6.99*10^-24

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