1) If the pressure on 55 mL vol. of a confined gas is increased from 720 mmHg to
ID: 548240 • Letter: 1
Question
1) If the pressure on 55 mL vol. of a confined gas is increased from 720 mmHg to 760 mmHg while temperature increased from 25°C to 34°C. What is the final volume? 2) Using the ideal gas law to calculate the mol of a gas at -23°C and.09 atm with a volume of 23mL 3) Define colligative properties and list four (4) of them: 4) In Ex: 12 there was a reaction between sulfamic acid and sodium nitrite which produced nitrogen, water and sodium bisulfate. (sulfamie acid is H:NSOsHes (A) Give the formula of the reactants (B) Write the complete reactiorn 5) The volume for the ideal perfect gas been determine to be 22.4133 L. Show how this value was calculated.Explanation / Answer
1.
Useful formula,
P1 V1 / T1 = P2 V2 / T2
720 * 55 / 298.15 = 760 * V2 / 307.15
V2 = Final volume = 537 mL
2.
P V = n R T
0.09 * 0.023 = n * 0.0821 * 296.15
n = 8.51 * 10-5 mol
3.
The properties of solution which depend only on the number of particles of solute but not on the nature of solute are called colligative properties.
They are,
a. Relative lowering of vapour pressure
b. Elevation in boiling point
c. Depression in freezing point
d. Osmotic pressure
4.
(a)
Sulphamic acid : H2NSO3H
Sodium nitrite: NaNO2
(b)
H2NSO3H + NaNO2 -----------> N2 + H2O + NaHSO4
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