6) What is the concentration of a second order reaction at 867 seconds if the ra

Question

6) What is the concentration of a second order reaction at 867 seconds if the rate constant is 0.0078 M-1-1 and its initial concentration was 0.888 M? A) 1.26x 10-1 M B)788 M 768 M D) 1.30 x 10-3 M what is the rate constant of a zero order reaction with a half life of 435 seconds and an initial concentration of 0.45 M? A) 2.07 x 10-3 Mis B)1.03 x 10-3 Ms 1.59 x 10-3 D) 5.16 x 10-4 M/s 8) it the concentration of a reactant at 34 seconds is 0.56 M and the rate constant is 0.034s-1, what was the initial concentration? (First order reaction) A) 6.47 x10-1 M B)1.58 M C) 1.78 M D) 2.04 x 101 9) Given the following proposed mechanism, predict the rate law for the overall reaction. 2002+a22N02a (overall reaction) Mechanism A) Rate-kINO2JICI) B) Rate-k[NO2][a2] D) Rate = k[N02ap

Explanation / Answer

6) K2 = 1/t[1/(a-x)-1/a]

a = initial concentration = 0.888 M

a-x = concentration after 867 sec = ?

t = 867 sec

k2 = 0.0078 M-1.S-1

0.0078 = (1/867)*((1/(a-x)-(1/0.888))

a-x = 0.126

answer: A

7) t1/2 = 435 sec , a = 0.45 M , a-x = 0.45/2 = 0.225 M

   K0 = a - (a-x) / t

      = (0.45 - 0.225)/435

   = 5.17*10^--4

answer: D

8) k1= (1/t)ln(a/a-x)

0.034 = (1/34)ln(a/0.56)

a = 1.78 M

answer: C) 1.78 M

9) rate law, rate = k[NO2][Cl2]

answer: B

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