1. A chemist recrystallizes 18.23 grams of a solid and recovered 11.11 grams as
ID: 549342 • Letter: 1
Question
1. A chemist recrystallizes 18.23 grams of a solid and recovered 11.11 grams as a first yield and 3.2 grams as a second yield obtained by boiling the mother liquor from the first batch. Calculate the total percent recovery. Put your answer in 3 significant figures.
2. The solubility of benzoic acid in water is 0.12 g/100 ml at 0oC and 7.04 g/100 ml at 100oC. Answer the following questions if 5.95 grams of benzoic acid were to be heated to boiling in 100 ml of water. What would be the maximum possible percent recovery if the solution was cooled to 0oC and vacuum filtered? Put your answer in 3 significant figures.
3. The solubility of benzoic acid in water is 0.09 g/100 ml at 0oC and 7.51 g/100 ml at 100oC. Answer the following questions if 5.07 grams of benzoic acid were to be heated to boiling in 100 ml of water. What would be the maximum possible percent recovery in a second batch, if the mother liquor was reduced to 49.2 ml, chilled in ice water and vacuumed filtered? Put your answer in 3 significant figures.
4.The solubility of benzoic acid in water is 0.12 g/100 ml at 0oC and 7.02 g/100 ml at 100oC. Answer the following questions if 4.98 grams of benzoic acid were to be heated to boiling in 100 ml of water. What would be the overall percent recovery if in a second batch, the mother liquor was reduced to 44.06 ml, chilled in ice water and vacuumed filtered? Put your answers in 4 significant figures.
Explanation / Answer
Question 1
A total weight of sample = 18.23 gm
First recovery = 11.11 gm
Second recovery = 3.2 gm
Total recovery = 11.11 +3.2 = 14.31 gm
Percentage recovery = 14.31 x 100 /18.23 = 78.49 %
Question 2
The solubility of benzoic acid in water at 0oC = 0.12 g/100 ml
Amount of benzoic acid dissolved 100oC = 5.07 g
Sample recovery = 5.07- 0.12 = 4.95 gm
Percentage recovery = 4.95 x 100 /5.07 = 97.63 %
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