The equation for enthalpy change ( H ) at constant pressure ( P ) is H = q P = E

Question

The equation for enthalpy change (H) at constant pressure (P) is

H = qP = E + PV,

where qP is the heat lost or gained at constant pressure, E is the change in the internal energy of the system, and V is the change in volume (V2 V1) of the system.

A sample of gas is maintained at a constant pressure of 2.60 atm. After 644 J of thermal energy is applied to (and absorbed by) the gas, its internal energy has increased by 511 J. By how much has the volume of the gas changed? (Include the sign of the value in your answer.)
L

Has it increased or decreased?

Explanation / Answer

H = E + PV

Give that Change internal Energy E = 511 j

Heat absorbed H = 644 j

Pressure P = 2.60 atm

Change in volume V =?

V = H-E/P

= 644-511/2.60 lit

= 51.153 lit

Change in Volume (V2 - V1) is positive that volume is increased

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