18 Question (3 points) See page 772 Starting with the standard free energies of

Question

18 Question (3 points) See page 772 Starting with the standard free energies of formation from the following table, calculate the values of AG° and E cel/of the following reactions. ubstance AGof(kJ/mol) FeO(s) H2(g) Fe(s) H200) Pb(s) 255.2 237.2 H2SO4(aq) -744.5 PbSO4(s) 813.0 1st attempt Part 1 (1point) See Hint FeO(s) + H2(g) Fe(s) + H20(1) kJ Part 2 (0 point) Fe0(s) +H2(g) _ Fe(s)+ H20(1) E"cell = Part 3 (1point) 2Pb(s) +02(g) +2H2SO4(aq)-2PbSO4(s) + 2H20(1) kJ Part4 (1 point) 2Pb(s) +02(g) + 2H2so, (ag)-2PbSO4 (s) + 2H20(1) E"cell=

Explanation / Answer

part 1

DG0 = (DG0f,H2O + DG0f,Fe)-(DG0f,H2 + DG0f,FeO(s))

      = (-237.2+0)- (0 + (-255.2))

      = +18 Kj

part 2

dg0 = - nFE0cell

18*10^3 = -2*96500*x

x = E0cell = -0.093 V

part 3

DG0 = (2*DG0f,H2O + 2*DG0f,PbSO4) - (2*DG0f,H2SO4 + DG0f,O2(g) + 2*DG0f,Pb)

   = (2*(-237)+2*(-813))-(2*(-744.5)+1*0+2*0)

   = -611 kj

part 4

dg0 = - nFE0cell

-611*10^3 = -4*96500*x

x = E0cell = 1.58 V

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