11. The following reaction is at equilibrium a. Does this reaction favor the rea

Question

11. The following reaction is at equilibrium a. Does this reaction favor the reactants or products at equilibrium? Explain your answerl2pts) b. Write the equilibrium constant expression for this reaction (3pts) What happens to this reaction when sulfur dioxide is removed from this system? Explain your answer.(3pts) c. d. Calculate the concentration of sulfur dioxide when [O] -0.00244 and [So,]-0.038 (4pts) 2. .0382 12. The following equation represents the formation of nitrogen dioxide, a major component of smog. 2NO + O2 2NO2 If 0.68 mole of NO is reacted with 0.79 mole of O2 to produce NO2, the limiting reagent is (2pts)

Explanation / Answer

11)

a )

reaction favours to forward direction that means products side.

it is due high Keq value . if Keq >>1 the reaction favors products and Keq <1 the reaction favors reactatns side

b)

Keq = [SO3]^2 / [SO2]^2 [O2]

c)

if SO2 removed the reaction shifts to backward direction .

according to lechatliers principle on increase in the concentration of any one of the reactant the reaction shits to forward direction (products side ) and on increase in concentration of any one of the product the reaction shifts to backward direction (reactants side)

d)

Keq = [SO3]^2 / [SO2]^2 [O2]

6.3 x 10^9 = (0.0138)^2 / [SO2]^2 x 0.00244

[SO2] = 3.52 x 10^-6 M

12)

2 NO + O2 ---------------> 2 NO2

2 mol   1 mol

0.68     0.79

moles ratio of NO = 0.68 / 2 = 0.34 less than that of O2

so limiting reagent is NO

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