In the land of Salad, there are two autosomal genes that (separately) determine
ID: 55050 • Letter: I
Question
In the land of Salad, there are two autosomal genes that (separately) determine two uniquephenotypes:
(i) Romaine lover (wild-type), Iceberg lover (recessive);
(ii) Thousand Island dressing lover (wild-type), Balsamic Vinaigrette lover (recessive).
We use the follow abbreviations for phenotypes:
Ro = Romaine Lover;
Ice = Iceberg Lover;
TI = Thousand Island Lover;
Ba = Balsamic Lover.
Two true-breeding parents, one who is a Iceberg and Balsamic lover, and the other who isRomaine, Thousand Island lover, are mated. One of the F1 offspring is back-crossed to a Iceberg, Balsamic lover. If the recombination between the two genes is 0.20, what are the expected counts of each phenotype from 500 F2 offspring?
A.Ice/Ba Ro/TI Ice/TI Ro/Ba
125 125 125 125
B. Ice/Ba Ro/TI Ice/TI Ro/Ba
200 100 100 50
C.Ice/Ba Ro/TI Ice/TI Ro/Ba
205 205 45 45
D. Ice/Ba Ro/TI Ice/TI Ro/Ba
225 225 25 25
E. Ice/Ba Ro/TI Ice/TI Ro/Ba
200 200 50 50
I feel the answer is E. This is because the recombination between the 2 genes is 0.20 or 20%.
Therefore, 0.2 * 500 = 100 is the total of recombination Ice/TI or Ro/Ba. Splitting equally, they get 50 each. The remaining 400 are split between parent genes Ro/TI and Ice/Ba as 200 each.
Can you please help me if I understood and got his correctly.
Explanation / Answer
In the land of Salad, there are two autosomal genes that (separately) determine
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