Given one of the following solutions: Remember your assigned solution C D E 50.0

Question

Given one of the following solutions: Remember your assigned solution C D E 50.00 mL 0.10M K-CrO 100.00 mL 0.10M CoCh 250.00 mL 0.10M KI 500.00 mL 0.1OM Ni(NOh 1000.00 mL 0.10M Cu(NO,) Answer the following questions concerning your assigned solution Be sure to SHOW WORK al 1. How do you prepare your solution ?-L- 2. What volume (mL) of your solution contains 5.00x 10 moles of the solute 3. 4. o What volume of your solution contains 1.00 g of the solute ? What is the new molarity of a solution made by pipeting 5.00 mL of your solution and diluting with 95.00 mL of deionized water ? For A,B, or C : What volurme of your solution is required to react with 10.00 mL of 0.10M Pb(NO3)2? For D or E: What volume of your salt is required to react with 10.00 mL 0. I0M e 5. Na2S ?

Explanation / Answer

if A is assigned,

50 mL of 0.1; K2CrO4

Q1.

solution can be prepaed by

M = mol/V

mol = MV = 50*0.1 = 5 mmol = 5*10^-3 mool

mass = molM W= (5*10^-3)(194.1903 ) = 0.970 g of K2CrO4 should be adde to V = 50 mL

Q2

find V for

n = 5*10^-4

M = mol/V

V = mol/M = (5*10^-4)/(0.1) = 0.005 Liter = 5 mL required

Q3

volume of solution containing 1 g

0.970 g of K2CrO4 should be adde to V = 50 mL

1 g = V

V = 1/0.97*50 = 51.55 mL required

Q4

M1V1=M2V2

0.1 * 5 = M2 * (95+5)

M2 = (0.1 * 5) / (95+5) = 0.005 M

Q5

mmol of Pb+2 = MV = 0.1*10 = 1

mmol of CrO4-2 required = 1

V = mmol/M = (1)/(0.1) = 10 mL required

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