At a certain temperature, the equilibrium constant K for the following reaction

Question

At a certain temperature, the equilibrium constant K for the following reaction is 5.6 × 10 H2(g) + 12(g) 2 HI(g) Use this information to complete the following table. Suppose a 21. Lreaction vessel is filled with 0.87 mol of H2 and 0.87 mol of I2. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and I2 There will be very little HI Neither of the above is true What is the equilibrium constant for the following reaction? Round your answer to 2 significant dinits 2H1(g) H2(g)+12(g) What is the equilibrium constant for the following reaction? Round your answer to 2 significant dinits 3H2(g)+312(g) 6H1(g)

Explanation / Answer

1)

Kc for the given reaction is very large

So, product will be dominating at equilibrium

so, there will be less reactants

Answer: There will be very little H2 and I2

2)

This reaction is reverse of given reaction,

K = 1/K1

= 1/(5.6*10^11)

= 1.8*10^-12

Answer: 1.8*10^-12

3)

This reaction is 3 times the given rection,

K = K1^3

= (5.6*10^11)^3

= 1.8*10^35

Answer: 1.8*10^35

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