Suppose your laboratory instructor inadvertently gave you a solid sample of KHP

Question

Suppose your laboratory instructor inadvertently gave you a solid sample of KHP that was contaminated with naCl to standardize your NaOH. You are unaware of this and use it to standardize the NaOH. The sodium chloride does not react base. how would this affect your calculated molarities for NaOH solution? explain your answer and be specific. Suppose your laboratory instructor inadvertently gave you a solid sample of KHP that was contaminated with naCl to standardize your NaOH. You are unaware of this and use it to standardize the NaOH. The sodium chloride does not react base. how would this affect your calculated molarities for NaOH solution? explain your answer and be specific. Suppose your laboratory instructor inadvertently gave you a solid sample of KHP that was contaminated with naCl to standardize your NaOH. You are unaware of this and use it to standardize the NaOH. The sodium chloride does not react base. how would this affect your calculated molarities for NaOH solution? explain your answer and be specific.

Explanation / Answer

The reaction of NaOH and KHP uses equimolar concentrations of both the reagents. Now if the sample of KHP is contaminated with NaCl , and since NaCl does not react with NaOH , KHP mass % in the sample that would react with NaCl will be low. Due to this , the end point of the reaction will occur earlier and NaOH volume utilised will be lower than normal. So a false reading will be obtained , that would over rate the molarity of base.

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