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what\'s the correct answer for these question some answer is not correct, I want

ID: 552505 • Letter: W

Question

what's the correct answer for these question some answer is not correct, I want to know the correct answer.

1· Thc two solvents you investigated in the laboratory were water and cyclohexane, C,H12 Consider three followi potential solutes: Disopropanol, CH3-CH-OH 2) 2-iodobutane, CH3- CH-CH2-CH3, CH3 3) lithium fluoride, LiF Fill in the table below by indicating whether you think these solutes will be soluble or insoluble in each of the tw solvents: (put "yes" for soluble and "no" for insoluble) Explain each prediction using "Like dissolves like" generalization Explanation HERE: Water Cyclo- hexane Thor s an al o ktgyaup in sopra isopropanol yes 2-iodobutane h o yes I no 1As ionic corpamd.lt wd( dende Lithium Fluoride Yes. . 2. You also measured the magnitude of the Boiling point of a substance. a) define Normal Boiling point The tenpretune that ouus trarstn f to ges uderl im b) Listed below are the values of the normal boiling point of several substances. Compare these values and expl the differences: (Hint: Consider what type(s) of intermolecular interactions are present in each substance) Substance Normal Boiling point, Deg C 68 C; 2-hexanone, CH eCH C 127 2-hexanol, CtH, EH-CH-CH-CHH 140° C 2-hexanone, CH.C (inleç ause2-levan( have OH - Il three subetances have london bo nt, 2 he nanone has- but leane hen the nomal bolig puht of 2 heranane s hiyher then hexane

Explanation / Answer

1) LiF is an ionic soli and dissociates into ions, Li+ and F- even in the solid state. Water, H2O is a polar compound. H2O is infact a dipole with the electronegative O atom acting as the negative pole and the electropositive H atom(s) acting as the positive pole. When LiF is dissolved in water, the positively charged Li+ is sheathed or surrounded by water molecules. The O atom can participate in ion-dipole interaction with Li+.

Similarly, the positively polarized H atom of H2O participates in ion-dipole interaction with the negatively charged F- atom. Due to these ion-dipole interactions, LiF is highly soluble in water.

Hexane is a non-polar solvent and cannot participate in ion-dipole interactions and hence, LiF is insoluble in hexane.

2a) The normal boiling point of a liquid is defined as the temperature where the vapor pressure of the vapor over the liquid equals the atmospheric pressure. The boiling point denotes the temperature when the liquid molecules can spontaneously pass into the vapor state.

2b) Hexane is a non-polar hydrocarbon. The forces of interactions in hexane are weak dispersion forces which can be easily overcome by supplying energy. Therefore, hexane has the lowest boiling point.

2-hexanone is a ketone. Though 2-hexanone contains a carbonyl (C=O) group, the molecule is not highly polar. This is due to the fact that long alkyl chain is non-polar in nature. The major forces of interaction are dispersion forces and dipole-dipole forces. The C=O group acts as a dipole with the C atom being positively polarized and the O atom negatively polarized. Dipole-dipole forces are stronger than dispersion forces and hence, 2-hexanone boils at a higher temperature than hexane.

The –OH group in 2-hexanol is highly polarized with the O atom being negative and the H atom positive. Infact, it is due to the high electronegativity of the O atom that the H atoms can participate in hydrogen bonding with the –OH group of an adjacent 2-hexanol molecule. Hydrogen bonding is a strong intermolecular force of attraction between a X-H bond (X = N, O, F) and an X atom (X = N, O, F) of a neighboring molecule. Hydrogen bonds are the strongest intermolecular forces and hence, 2-hexanol has the highest boiling point.

3a) The method of least squares is often employed to find out the rate of a reaction. The second graph gives the best fit of a straight line. The best fit is adjudged from the R2 value. The graph I-2 has the highest R2 value (close to 1.0000). Therefore, the rate of the reaction is first order with respect to C4H9Cl.