Show your calculations for each determination in the space provided. Remember to

Question

Show your calculations for each determination in the space provided. Remember to include units with allca culated results. II. Titrating the Fruit Juice 1. Calculate the volume, in mililiters, of NaOH solution required for the ttration. ga,2-45 determination 1 determination 2 2. Calculate the number of moles of NaoH required for the titration, using Equation 2 -3 3 determination 2 4OIo determination 1 1.60XI0 3. Calculate the number of moles of H3CGHo, titrated, using Equation 3 determination 2 determination 1 4. Calculate the mass of HyCoH,o, present in the julce sample, using Equation 4. determination 2 determination 1

Explanation / Answer

According to chegg rules we have to answer only first four questions.

1.

Given that, for determination 1

Initial buret reading = 45 ml

Final butet reading = 27.2 ml

Volume of NaOH used in ml = 45-27.2 = 17.8 ml

for determination 2

Initial buret reading = 45 ml

Final butet reading = 26.2 ml

Volume of NaOH used in ml = 45-26.2 = 18.8 ml

2.

Molarity of NaOH= 0.1024 M or mole/L

Number of moles = molarity * volume in L

For determination 1:

Number of moles = molarity * volume in L

=0.1024 mole/L * 17.8 ml * 1 .0L / 1000 ML

= 1.82*10^-3 Mole NaOH

For determination 2:

Number of moles = molarity * volume in L

=0.1024 mole/L * 18.8 ml * 1 .0L / 1000 ML

= 1.92*10^-3 Mole NaOH

3.

Citric acid (H3C6H5O7) and NaOH reacted as follows:

H3C6H5O7 (aq)+ 3NaOH (aq) --- > Na3C6H5O7 (aq) + 3H2O (l)

Number of mole of citric acid is calculate as follows:

For determination 1:

1.82*10^-3 Mole NaOH *1 mole H3C6H5O7/ 3 mole NaOH

= 6.1*10^-4 mole H3C6H5O7

For determination 2:

1.92*10^-3 Mole NaOH *1 mole H3C6H5O7/ 3 mole NaOH

= 6.4*10^-4 mole H3C6H5O7

4.

Mass of citric acid = number of mole s* molar mass

Molar mass of citric acid = 192.124 g/mole.

Determination 1:

Mass of citric acid = number of mole s* molar mass

=6.1*10^-4 mole H3C6H5O7 *192 .124 g/ mole

= 0.117 g citric acid

Determination 2:

Mass of citric acid = number of mole s* molar mass

=6.4*10^-4 mole H3C6H5O7 *192 .124 g/ mole

= 0.123 g citric acid

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